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8πcm/2πr=1/12 /×12
96πcm/2πr=1 /÷2πr
96πcm=2πr /÷2π
48cm=r
Pw (pole wycinka)= 1/12πr²
Pw=1/12π*48²
PW=1/12π*2304
Pw=192π cm²
8pi=2pi*r*30/360
6r=8
r=3/4
Poloe koła =pi*r(kwadrat)
P=3/4(kwadrat)*pi
P=9/16 pi (cm(kwadratowych))