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{(A,A),(A,G),(G,A),(G,G)}
Keduanya angka ada 1 sampel, n(A) = 1
Dari keseluruhan 4 sampel, n(S) = 4
Sehingga:
P(A) = n(A)/n(S)
P(A) = 1/4
Untuk frekuensi harapan, n = 56
Maka,
FH(A) = P(A) x n
FH(A) = 1/4 x 56
FH(A) = 14 kali
Sehingga, frekuensi harapannya ada 14 kali.