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n(A)= (1,1), (1,3), (1,4), (2,2), (2,3), (2,6), (3,1), (3,2), (3,5), (4,1), (4,4), (4,6), (5,3), (5,5), (6,2), (6,4) = 16
n (s) = 36
P (A) = n(A)/n(S)= 16/36=4/9
Frekuensi harapan= PAxbanyaknya percobaan
..........................= 4/9x180
.........................= 80 kali <-------------- jawaban (c)
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