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Q1 = 30 μC = 3x10⁻⁵ C
Q2 = 20 μC = 2x10⁻⁵ C
r = 600 cm = 6 m
Ditanyakn : E terhadap Q1 ?
Dijawab :
F = k Q1Q2/r²
= 9x10⁹ x 3x10⁻⁵ x 2x10⁻⁵/6²
= 54x10⁻¹/36
= 1,5x10⁻¹
Jadi :
E = F/Q2
= 1,5x10⁻¹/2x10⁻⁵
= 0,75x10⁴
= 7.500 N/C