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Verified answer
Materi : ListrikSub bab : Gaya Coulomb
Diketahui :
q1 = 60 μC = 60x10^-6 C = 6x10^-5 C
q2 = 40 μC = 40x10^-6 C = 4x10^-5 C
r = 20 cm = 0,2 m
Ditanya :
F = ?
Penyelesaian :
F = k. q1q2/r²
F = 9x10^9 (6x10^-5)(4x10^-5) / (0,2)²
F = 216x10^-1 / 0,04
F = 5400 x 10^-1
F = 540 N
Jadi, besarnya gaya coulomb yg bekerja adalah 540 N
Jawaban : tidak ada di opsi
semoga membantu
-vin