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n(a)={(1,4)(3,2)}->p(a)=2/36=1/18
->p(b)=1/36
sorry klo saya salah
n(b)={(1,6)}
(1, 1)(1, 2)(1, 3)(1, 4)(1, 5)(1, 6)
(2, 1)(2, 2)(2, 3)(2, 4)(2, 5)(2, 6)
(3, 1)(3, 2)(3, 3)(3, 4)(3, 5)(3, 6)
(4, 1)(4, 2)(4, 3)(4, 4)(4, 5)(4, 6)
(5, 1)(5, 2)(5, 3)(5, 4)(5, 5)(5, 6)
(6, 1)(6, 2)(6, 3)(6, 4)(6, 5)(6, 6)
= 36 kejadian
kejadian dengan jumlah 5 = (1, 4)(2, 3)(3, 2)(4, 1)
= 4 kejadian
kejadian dengan jumlah 7 = (1, 6)(2, 5)(3, 4)(4, 3)(5, 2)(6, 1)
= 6 kejadian
Karena yang ditanyakan dengan jumlah 5 atau 7, maka ditambahkan karena dua-duanya memenuhi persyaratan :
4 + 6 = 10
peluang = 10 / 36
= 5 / 18