" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Según gráfico: ΔABC
Utilizar triangulo notable de 30° en ΔCHA
AH / 20 = √3 / 2
AH = 10√3
CH / 20 = 1 / 2
CH = 10
Utilizar: teorema de pitagoras en ΔCHB
c² = a² + b²
Hallar lado: BC
BC² = CH² + (HA + AB)²
BC² = CH² + (AH + AB)²
BC² = 10² + (10√3 + 15)²
BC² = 100 + (10(1.732) + 15)²
BC² = 100 + (17.32 + 15)²
BC² = 100 + (32.32)²
BC² = 100 + 1044.615
BC² = 1144.615
BC = √1144.615
BC = 33.832 millas