Do zrobienia 8 zadań
1.
y=-2x² -8x -6
a=-2
b=-8
c=-6
Δ=b²-4ac
Δ=64-48=16
x₁= (-b-√Δ)2a
x₁=(8-4)/-4 = 4/-4 = -1
x₂=(-b+√Δ)/2a
x₂=(8+4)/-4 = 12/-4 = -3
x₀∈{-1;-3}
postac iloczynowa;
y=a(x-x₁)(x-x₂)
y=-2(x+1)(x+3)
postac kanoniczna;
y=a(x-p)²+q
W=(p;q)
p=(x₁+x₂)/2
p=[-1+(-3)]/2=-4/2=-2
q=f(p)=-2(-2+1)(-2+3)=-2
W=(-2;-2)
y=-2(x+2)²-2
2.
a)
(x-2)²+2(3x-4)=6x-8
x²-4x+4+6x-8-6x+8=0
x²-4x+4=0
a=1
b=-4
c=4
Δ=16-16=0
x₀=-b/2a=4/2=2
b)
x⁴-8x-9=0
(x²)²-8x²-9=0
(x²)²-(2√2x)²-3²=0/√
x²-2√2x-3=0
b=-2√2
c=-3
Δ=8+12=20
3.
(x+2)<2x²+3x+2
-x²+x+2<0/:(-1)
x²-x-2>0
Δ=1+8=9
√Δ=3
x₁=(1-3)/2=-2/2=-1
x₂=(1+3)/2=4/2=2
x₀∈(-∞;-1>u<2;∞)
x²-6x+9≤0
Δ=36-36=0
x₀=-b/2a=6/2=3
x∈{3}
4.
P=a×b
a₁=x
b₁=x+3
P₁=x×(x+3)=x²+3x
a₂=x
b₂=x+3-4
P₂=x×(x-1)=x²-x
P₁=½P₂
2P₁=P₂
2(x²+3x)=(x²-x)
2x²+6x-x²+x=0
x²+7x=0
y=-3x²+6x+9
a=-3
b=6
c=9
Δ=36+108=144
√Δ=12
x₁=(-6-12)/-6=-18/-6=3
x₂=(-6+12)/-6=6/-6=-1
x₀∈{3;-1}
p=(x₁+x₂)/2=(3-1)/2=2/2=1
q=f(p)=-3×1²+6×1+9=-3+6+9=12
W=(1;12)
y=-3(x-3)(x+1)
y=-3(x-1)²+12
(x+3)²+6x+2=2(3x+1)
x²+6x+9+6x+2-6x-2=0
x²+6x+9=0
x₀=-b/2a=-6/2=-3
x⁴-3x²-4=0
3 .
(x-2)²<2x²-3x-2
x²-4x+4-2x²+3x+2<0
-x²-x+6<0/×(-1)
x²+x-6>0
b=1
Δ=1+24=25
√Δ=5
x₁=(-1-5)/2=-6/2=-3
x₂=(-1+5)/2=4/2=2
x₀={-3;2}
x∈(-∞;-3)u(2;∞)
x²-2x+4≥0
b=-2
Δ=4-16=-12
x∈R
Ob.=2km=2000m
e=x
f=x+200
P=(e×f)/2
P=[x×(x+200)]/2=(x²+200x)/2=½x²+100x
Ob.=a×4=2000
a=500
nie cale ale troche pomoglam...;)wiecej nie umiem:(
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1.
y=-2x² -8x -6
a=-2
b=-8
c=-6
Δ=b²-4ac
Δ=64-48=16
x₁= (-b-√Δ)2a
x₁=(8-4)/-4 = 4/-4 = -1
x₂=(-b+√Δ)/2a
x₂=(8+4)/-4 = 12/-4 = -3
x₀∈{-1;-3}
postac iloczynowa;
y=a(x-x₁)(x-x₂)
y=-2(x+1)(x+3)
postac kanoniczna;
y=a(x-p)²+q
W=(p;q)
p=(x₁+x₂)/2
p=[-1+(-3)]/2=-4/2=-2
q=f(p)=-2(-2+1)(-2+3)=-2
W=(-2;-2)
y=-2(x+2)²-2
2.
a)
(x-2)²+2(3x-4)=6x-8
x²-4x+4+6x-8-6x+8=0
x²-4x+4=0
a=1
b=-4
c=4
Δ=16-16=0
x₀=-b/2a=4/2=2
b)
x⁴-8x-9=0
(x²)²-8x²-9=0
(x²)²-(2√2x)²-3²=0/√
x²-2√2x-3=0
a=1
b=-2√2
c=-3
Δ=8+12=20
3.
a)
(x+2)<2x²+3x+2
-x²+x+2<0/:(-1)
x²-x-2>0
Δ=1+8=9
√Δ=3
x₁=(1-3)/2=-2/2=-1
x₂=(1+3)/2=4/2=2
x₀∈(-∞;-1>u<2;∞)
b)
x²-6x+9≤0
Δ=36-36=0
x₀=-b/2a=6/2=3
x∈{3}
4.
P=a×b
a₁=x
b₁=x+3
P₁=x×(x+3)=x²+3x
a₂=x
b₂=x+3-4
P₂=x×(x-1)=x²-x
P₁=½P₂
2P₁=P₂
2(x²+3x)=(x²-x)
2x²+6x-x²+x=0
x²+7x=0
1.
y=-3x²+6x+9
a=-3
b=6
c=9
Δ=36+108=144
√Δ=12
x₁=(-6-12)/-6=-18/-6=3
x₂=(-6+12)/-6=6/-6=-1
x₀∈{3;-1}
W=(p;q)
p=(x₁+x₂)/2=(3-1)/2=2/2=1
q=f(p)=-3×1²+6×1+9=-3+6+9=12
W=(1;12)
postac iloczynowa;
y=a(x-x₁)(x-x₂)
y=-3(x-3)(x+1)
postac kanoniczna;
y=a(x-p)²+q
y=-3(x-1)²+12
2.
(x+3)²+6x+2=2(3x+1)
x²+6x+9+6x+2-6x-2=0
x²+6x+9=0
a=1
b=6
c=9
Δ=36-36=0
x₀=-b/2a=-6/2=-3
b)
x⁴-3x²-4=0
3 .
a)
(x-2)²<2x²-3x-2
x²-4x+4-2x²+3x+2<0
-x²-x+6<0/×(-1)
x²+x-6>0
a=1
b=1
c=-6
Δ=1+24=25
√Δ=5
x₁=(-1-5)/2=-6/2=-3
x₂=(-1+5)/2=4/2=2
x₀={-3;2}
x∈(-∞;-3)u(2;∞)
b)
x²-2x+4≥0
a=1
b=-2
c=4
Δ=4-16=-12
x∈R
4.
Ob.=2km=2000m
e=x
f=x+200
P=(e×f)/2
P=[x×(x+200)]/2=(x²+200x)/2=½x²+100x
Ob.=a×4=2000
a=500
nie cale ale troche pomoglam...;)wiecej nie umiem:(