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czyli na 66 sposobów można wybrać z n drużyn dwie
(n nad 2) = n!/[2!*(n - 2)!] = 66
n!/[2!*(n - 2)!] = 66
(n - 2)!*(n - 1)*n/[2!*(n - 2)!] = 66
(n - 1)*n = 66*2!
(n - 1)*n = 132
n² - n - 132 = 0
Δ = 1 + 528 = 529 = 23*23
n > 0 => n = (1 + 23)/2 = 12
jak masz pytania to pisz na pw