Do ogrzania kulki pewnego metalu omasie 0,7 kg o 10 stopni Celsjusza potrzeba 1050J energii. Oblicz siepło właściwe tego metalu.
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
m = 0,7 kg
ΔT = 10⁰ C
Q = 1050 J
cw = ?
Q = m * cw * ΔT
cw = Q /m *ΔT
cw = 1050 J /0,7 kg * 10⁰C
cw = 150 J/kg * ⁰C
m = 0,7 kg
Q = 1050 J
cw = 1050/(0,7 * 10 ) = 150 J/kg * ⁰C