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mK=39u
2C6H5OH + 2K ------->2C6H5OK + H2
2*94g fenolu--------2*39g potasu
xg fenolu------------2g potasu
x=4,8g fenolu
W nadmiarze użyto fenolu
2*39g potasu------22,4dm3 wodoru
2g potasu------------xdm3 wodoru
x=0,57dm3 wodoru