Do kolby zawierającej 92g H2O dodano 8g Potasu.Oblicz stężenie procentowe otrzymanego roztworu wodorotlenku potasu.
ms=8g
mw=92g
mr=ms+mw
mr=92g+8g=100g
Cp=?
Cp=ms/mr*100%
Cp=8g/100g*100%=8%
Cp=8%
Cp=ms*100%/mr
mrozp=92g
mr=ms+mrozp=8g+92g=100g
Cp=8g*100%/100g=8%
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ms=8g
mw=92g
mr=ms+mw
mr=92g+8g=100g
Cp=?
Cp=ms/mr*100%
Cp=8g/100g*100%=8%
Cp=8%
Cp=ms*100%/mr
ms=8g
mrozp=92g
mr=ms+mrozp=8g+92g=100g
Cp=8g*100%/100g=8%