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Na - ilość sodu (g)
W+Na - ilośc roztworu solanki (g)
czyli Na / (W+Na) = 5 %= 0,05, stąd ilość Na = 4 g,
po dolaniu wody ilośc Na = const, ale W+Na = 80g + 20 g=100 g,
czyli 4g/100g= 0,04 czyli 4 %
80g - 100%
x - 5%
x=80*5/100=4g - masa soli w naszej solance
Mr2= 80g + 20g =100g
100g - 100%
4g - x
x=100*4/100=4%
Odp. Stezenie solanki po dolaniu 20g wody wynosi 4%
pozdro:)
cp=5%
mw=20g
cp1=?
cp=ms*100%/mr
ms=cp*mr/100%=5%*80g/100%=4g
mr1=mr+mw=80g+20g=100g
cp1=ms*100%/mr1=4g*100%/100g=4%