Question

Do 60gr 12% roztworu soli dodano 20gr tej samej soli. Oblicz stężenie % powstałego roztworu.

Answer 1

msdodanej=20g   mr1=60g   Cp1=12%

 

 

 

mr2=mr1+ms dod

mr2=60g+20g

mr2=80g

 

ms1=mr1*Cp1/100%

ms1=60g*12%/100%

ms1=7,2g

 

ms2=ms1+ms dod

ms2=7,2g+20g

ms2=27,2g

 

Cp2=ms2*100%/mr2

Cp2=27,2g*100%/80g

Cp2=34%

Answer 2

60g=mr1 cp1-12%=0,12 cp=ms/mr*100% cp*mr=ms 0,12*60=ms ms=7,2 mr=ms+mrozpuszczalnika mrozp.=60-7,2=52,8 ms2=ms+20g ms2=7,2+20=27,2g cp2=(27,2/27,2+52,8)*100%=34%