Do 40 gram 20-procentowego roztworu kwasu siarkowego (VI) dodano 10 g wody. Oblicz stężenie procentowe tak otrzymanego roztworu.
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40g*20%+10g*0%=(40g+10g)x%
800=50x
x=16[%]
mr1= 40g
Cp1= 20%
ms= (Cp * mr)/100%= 8 g
mr2= mr1 + 10g= 50g
Cp= (ms*100%)/mr2= 8*100/50=16%