oblicz stężenie jonów wodorotlenkowych, jeśli
a) pH=4,6
b) pH=9,3
c) [H+] =2,3 * 10^-3 mol/dm3
d) [H+] =5,4 * 10^-4 mol/dm3
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a) pH=4,6
pH + pOH = 14
pOH = 9,4
[OH⁻] = 10^-9,4
[OH⁻] = 3,98*10⁻¹⁰ mol/dm³
b) pH=9,3
pOH = 4,7
[OH⁻] = 10^-4,7
[OH⁻] = 2*10⁻⁵ mol/dm³
c) [H+] =2,3 * 10^-3 mol/dm3
[H+] * [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 2,3*10⁻³
[OH⁻] = 4,3*10⁻¹² mol/dm³
d) [H+] =5,4 * 10^-4 mol/dm3
[H+] * [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 5,4*10⁻⁴
[OH⁻] =1,85*10⁻¹¹ mol/dm³