2 CnH2n+1-COOH + Zn ----> (CnH2n+1-COO)2Zn + H2
3,7 g 0,56dm3
2 M 22,4dm3
M = 3,7 x 22,4 / 0,56 x 2 = 74 g
masa COOH = 12 + 16 + 16 + 1 = 45
Masa CnH2n+1 = 74 - 45 = 29g
Czyli to kwas C2H5COOH - propanowy
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2 CnH2n+1-COOH + Zn ----> (CnH2n+1-COO)2Zn + H2
3,7 g 0,56dm3
2 M 22,4dm3
M = 3,7 x 22,4 / 0,56 x 2 = 74 g
masa COOH = 12 + 16 + 16 + 1 = 45
Masa CnH2n+1 = 74 - 45 = 29g
Czyli to kwas C2H5COOH - propanowy