Gęstość par pewnego alkanu wynosi 1,94 g/dm3. Podaj wzór i nazwę tego węglowodoru.
1,94g alkanu-----1dm3
xg alkanu---------22,4dm3
x ≈ 44g alkanu
Wzór ogólny alkanu: CnH2n+2
CnH2n+2 = 44
12n+2n+2 = 44
14n = 42
n = 3
Szukany alkan to: C3H8 (propan)
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1,94g alkanu-----1dm3
xg alkanu---------22,4dm3
x ≈ 44g alkanu
Wzór ogólny alkanu: CnH2n+2
CnH2n+2 = 44
12n+2n+2 = 44
14n = 42
n = 3
Szukany alkan to: C3H8 (propan)