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d C2H4 - 8,8g-CO2
28g = 88g
d = 2,8g
mC = 2*12u = 24u
mH = 4*1u = 4u
mC2H4 = 28u
V= m/d
V= 2,8g/1,15g/dm3 = 2,43dm3
odp. Objętość etenu wynosi 2,43dm3.