Dla każdegoo z ciągów: an=4n-3, bn=n²+1
a) oblicz: a₁,a₁₀,a₈₄,a₁₅₀,a₂₈₀
b) oblicz: S₁₀
Dziękuję
an=4n-3,
n=1
a1 = 1
a2 = 5
r=4
a10 = a1+9r = 1+36 = 37
a84 = a1+83r = 1+83*4 = 333
a150 = a1+149r = 1+596=597
a280=a1+279r = 1117
S10 = (a1+a1+9r)/2 *10 = (38/2 )*10 = 190
bn=n²+1
b1 = 2
b2 = 5
r=5-2 =3
b10 = b1+9r = 2+27=29
b84= b1+83r = 251
b150 = b1+149r = 2+447 = 449
b280 = b1+279r = 2+837 = 839
s10 = (a1+a1+9r)/2 * 10 = (4+27)/2 *10 = 155
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an=4n-3,
n=1
a1 = 1
a2 = 5
r=4
a10 = a1+9r = 1+36 = 37
a84 = a1+83r = 1+83*4 = 333
a150 = a1+149r = 1+596=597
a280=a1+279r = 1117
S10 = (a1+a1+9r)/2 *10 = (38/2 )*10 = 190
bn=n²+1
b1 = 2
b2 = 5
r=5-2 =3
b10 = b1+9r = 2+27=29
b84= b1+83r = 251
b150 = b1+149r = 2+447 = 449
b280 = b1+279r = 2+837 = 839
s10 = (a1+a1+9r)/2 * 10 = (4+27)/2 *10 = 155