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Δ = (2m - 3)^2 - 4 * 1 * (2m + 5) = 4m^2 - 12m + 9 - 8m - 20 = 4m^2 - 20m - 11
1. Δ > 0
4m^2 - 20m - 11 > 0
Δ(m) = 400 - 4 * 4 * (-11) = 400 + 176 = 576
√Δ = 24
m1 = (20 - 24)/8 = -4/8 = -1/2
m2 = (20 + 24)/8 = 44/8 = 11/2
m nalezy (-oo, -1/2) u (5,5 ; +oo)
2. x1 * x2 < 0
c/a < 0
(2m + 5) / 1 < 0
2m + 5 < 0
2m < -5
m < -2,5
m nalezy (-oo, ; -2,5)
Szukamy teraz części wspólnej tych dwóch odpowiedzi i otrzymujemy
odp. m nalezy (-oo, ; -2,5)