February 2019 0 101 Report
Dla jakich wartości parametru m równanie ma jedno rozwiązanie? Dla znalezionych wartości m oblicz pierwiastki danego równania:
a) x^2-2mx+2m^2+m-6=0 \\ b) (m-1)x^2-(m^2-1)x+m^2+m=0
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