a) a=√2, b= -1 , c=0
f(x) = √2 x² -x b) a=2+√3, b=-3√2-11 , c=6
f(x) = (2+√3)x² - (3√2+11)x + 6 c) a=√3-1, b=∛5, c=-1,7
f(x) = (√3-1)x² + ∛5x - 1,7
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a)f(x)=√2x²-x
b)f(x)=(2+√3)x²-(3√2+11)x+6
c)f(x)=(√3-1)x²+∛5x-1,7
jeśli pomogłem, liczę na naj;)
a) a=√2, b= -1 , c=0
f(x) = √2 x² -x
b) a=2+√3, b=-3√2-11 , c=6
f(x) = (2+√3)x² - (3√2+11)x + 6
c) a=√3-1, b=∛5, c=-1,7
f(x) = (√3-1)x² + ∛5x - 1,7