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b = 2
c = 1
sifat PK, jika a = c, maka D = 0
pembuktian
D = b² - 4ac
D = 2² - 4 × 1 × 1
D = 4 - 4
D = 0
x² +2x +1 = 0
a = 1
b = 2
c = 1
D = b² -4ac
= (2)² -4(1)(1)
= 4 -4
= 0
Jadi, nilai diskriminannya adalah 0.
Itu jawabannya.