Matematika
v(t) = 10t - 2
s(t) = int 10t - 2
= 5t² - 2t + c
pada awalnya sepeda motor berjarak 5 m
s(0) = 5
s(0) = 5(0)² - 2(0) + c
5 = 0 - 0 + c
5 = c
maka
s(t) = 5t² - 2t + 5
Jarak sepeda motor detik ke 5
s(5) = 5(5)² - 2(5) + 5
= 5(25) - 10 + 5
= 125 - 5
= 120 m
Jawaban terdapat di lampiran
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Matematika
v(t) = 10t - 2
s(t) = int 10t - 2
= 5t² - 2t + c
pada awalnya sepeda motor berjarak 5 m
s(0) = 5
s(0) = 5(0)² - 2(0) + c
5 = 0 - 0 + c
5 = c
maka
s(t) = 5t² - 2t + 5
Jarak sepeda motor detik ke 5
s(5) = 5(5)² - 2(5) + 5
= 5(25) - 10 + 5
= 125 - 5
= 120 m
Jawaban terdapat di lampiran