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³ log 7 =b => log 7=b log 2
42 log 56
=>log 56 / log 42
=>log 7 + log 8 / log 2+ log 3 + log 7
=>b log 2 + 3 log 2 / log 2 + a log 2 + b log 2
=>log 2 (b + 3) / log 2 (1 + a + b)
=>(b+3) / (1+a+b)
= 2log8 + 2log7 / 2log6 + 2log7 = 3+2log7 / 1+ 2log3 + 2log7 = 3+ 3log7/3log2 per
1+3log7/3log2 = 3+ab/ 1+ab