Diketahui y = tan x , persamaan garis singgung di titik (π per 4) adalah? a. y = 2x + 1 - π per 4 b. y = 2x + 1 - π per 2 c. y = 2x - 1 - π per 2 d. y = 1 per 2x - 1 - π per 8 e. y = 1 per 2x + 1 + π per 8 Mohon jawab dengan caranya :)
DB45
Jawab B . y = tan x x = π/4 --> y = tan π/4 = 1 titik singgung (x1,y1) = (π/4 , 1)
m = y' = sec² x x = π/4 --> m = (sec π/4)² = (√2)² = 2
pers garis singgung y = m(x - x1) + y1 y = 2(x - π/4) + 1 y = 2x - π/2 + 1 y = 2x + 1 - π/2
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y = tan x
x = π/4 --> y = tan π/4 = 1
titik singgung (x1,y1) = (π/4 , 1)
m = y' = sec² x
x = π/4 --> m = (sec π/4)² = (√2)² = 2
pers garis singgung y = m(x - x1) + y1
y = 2(x - π/4) + 1
y = 2x - π/2 + 1
y = 2x + 1 - π/2