Materi : Koordinat Kartesius
AB² = (∆x)² + (∆y)²
AB² = (7 - 5)² + (6 - 3)²
AB² = 2² + 3²
AB² = 4 + 9
AB² = 13
AB = √13 satuan
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
..
[tex]Jarak~a \to b= \sqrt{(x_{b} - x_{a}) {}^{2} + (y_{b} - y_{a}) {}^{2} } [/tex]
[tex]Jarak= \sqrt{(7 - 5) {}^{2} + (3- 6) {}^{2} } [/tex]
[tex]~~~~~~~~~~~~= \sqrt{2 {}^{2} + ( - 3) {}^{2} } [/tex]
[tex]~~~~~~~~~~~~= \sqrt{4 + 9} [/tex]
[tex]~~~~~~~~~~~~=\boxed{ \sqrt{13} }[/tex]
[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{10/03/23}}[/tex]
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Materi : Koordinat Kartesius
AB² = (∆x)² + (∆y)²
AB² = (7 - 5)² + (6 - 3)²
AB² = 2² + 3²
AB² = 4 + 9
AB² = 13
AB = √13 satuan
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Koordinat Kartesius
[Jarak]
..
[tex]Jarak~a \to b= \sqrt{(x_{b} - x_{a}) {}^{2} + (y_{b} - y_{a}) {}^{2} } [/tex]
..
Diberikan
Tentukan
Hasil dan Perhitungan
[tex]Jarak= \sqrt{(7 - 5) {}^{2} + (3- 6) {}^{2} } [/tex]
[tex]~~~~~~~~~~~~= \sqrt{2 {}^{2} + ( - 3) {}^{2} } [/tex]
[tex]~~~~~~~~~~~~= \sqrt{4 + 9} [/tex]
[tex]~~~~~~~~~~~~=\boxed{ \sqrt{13} }[/tex]
..
[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{10/03/23}}[/tex]