Diketahui tabung dengan tinggi 10 cm dan luas selimutnya 1.320 cm hitunglah: a.jari jari alas b. volum c. luas permukaan tabung
ranaaarr
A. L.selimut = 2πrt 1.320 = 2πrt 1.320 = πrt 660 = π.r.10 = π.r 66 : = r r = 21 cm b. V.tabung = L.alas x tinggi = πt = x 21 x 21 x 10 = 13.860 c. L.alas+atap = 2 x ( x 21 x 21) = 2 x 1.386 = 2.772 L.perm seluruhnya = 2.772 + 1.320 = 4.092
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afifabdilah123
Luas selimut tabung = 2rt 1320= 2*10*r*22/7 1320*7=440r 9240/440=r => r= 21 cm V= V=13860 LP= 4092
1.320 = 2πrt
1.320 = πrt
660 = π.r.10
= π.r
66 : = r
r = 21 cm
b. V.tabung = L.alas x tinggi
= πt
= x 21 x 21 x 10
= 13.860
c. L.alas+atap
= 2 x ( x 21 x 21)
= 2 x 1.386
= 2.772
L.perm seluruhnya = 2.772 + 1.320 = 4.092
1320= 2*10*r*22/7
1320*7=440r
9240/440=r => r= 21 cm
V=
V=13860
LP= 4092