Diketahui segitiga ABC siku-siku di A, jika panjang AB = 12cm dan BC = 14cm. Berapakah nilai cosinus B ?
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Cari panjang AB:
AB² = BC² - AC²
AB² = 14² - 12²
AB² = 196 - 144
AB² = 52
AB = √52 cm
AB = 2√13 cm
Cosinus B
= sisi samping/sisi miring
= AB/BC
= 2√13/14
= √13/7