Diketahui segi empat ABCD dengan AB=2x cm,BC=(3x-17) cm,CD=(15-x) cm dan DA=(5+x).keliling segi empat tersebut 53 cm.Nilai x =
anjhanijasmine
Keliling segi empat = ab + bc + cd+ da 53 = 2x + 3x - 17 + 15 - x + 5 + x 53 = 5x + 3 5x = 53 - 3 5x = 50 x = 50/5 x = 10 subtitusikan nilai x=10 ke masing masing panjangssegi 4 tersebut ab = 2x cd = 15 - x = 2 . 10 = 15 - 10 = 20 cm = 5 cm bc = 3x - 17 da = 5 + x = 3.10 - 17 = 5 + 10 = 30 - 17 = 15 cm = 13
53 = 2x + 3x - 17 + 15 - x + 5 + x
53 = 5x + 3
5x = 53 - 3
5x = 50
x = 50/5
x = 10
subtitusikan nilai x=10 ke masing masing panjangssegi 4 tersebut
ab = 2x cd = 15 - x
= 2 . 10 = 15 - 10
= 20 cm = 5 cm
bc = 3x - 17 da = 5 + x
= 3.10 - 17 = 5 + 10
= 30 - 17 = 15 cm
= 13