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n(A) = 5
B = (3, 4, 5}
n(B) = 3
n(A u B) = (2, 3, 4, 5, 6}
n(A u B) = 5
b. S = {1, 2, 3, 4, 5, 6}
n(S) = 6
(A n B) = {3, 4, 5}
n(A n B) = 3
n(S) ... n(A) + n(B) - n(A n B) + n(A n B)
6 ... 5 + 3 - 3 + 3
6 ... 8
6 ≠ 8