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u2=5(2)-3=7
u3=5(3)-3=12
u4=5(4)-3=17
u5=5(5)-3=22
u6=5(6)-3=27
jumlah 6suku pertama
=u1+u2+u3+u4+u5+u6
=2+7+12+17+22+27
=87
jawaban pasti benar