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f(3)=14 3a+b=14
eliminasi kedua persamaan sehingga didapat 2a=10 a=5
a+b=4
5+b=10
b=-1
f(x)=ax+b
=5x-1
f(3)= a(3)+b=14 -->3a+b=14....persamaan 1
f(1)= a(1)+b=4 --> 1a+b=4.....persamaan 2
------------- -
2a = 10
2a=10
a=10/2
a=5
(pilih salah satu antara persamaan 1 dan 2) *bebas
(aku pilih persamaaan 2)
a=5
1a+b=4
1(5)+b=4
5+b=4
b=4-5
b= -1
jadi hasil rumusnya adalah.. 5x-1
bila f(-4) jawabnya:
f(x)= 5x-1
f(-4)= 5(-4)-1
= -20-1
= -21