Diketahui: r1=6cm
r²=18cm
s¹=28cm
ditanya :volume kerucut?
tolong dongg kk
r²=18cm
s¹=28cm
ditanya :volume kerucut?
tolong dongg kk
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Penjelasan dengan langkah-langkah:
Volume kerucut terpancung
Diket :
Dit :
Volume
Jawab :
tInggi kerucut
= √(28)²-(18-6)²)
= √(28)²-(12)²)
= √(784)-144)
= √640
= 8√10 cm
Maka Volume Kerucut terpancung tsb
= ⅓ π t ( Rr + R + r )
= ⅓ . 3,14 . 8√10 ( 18.6 + 18 + 6 )
= ⅓ . 3,14 . 8√10 (108+24)
= ⅓ . 3,14 . 8√10 (132)
= 3,14 . 8√10 . 44
= 1105,28√10 cm³ ✓
T.K :
= √28² - (18 - 6)²
= √(28(28) - 12²
= √784 - (12(12)
= √784 - 144
= √640
= 25,40 CM
MAKA :
V = 1/3(3,14(25,40) + (18 × 6) + (18 + 6)
= 1/3(79,756(108 + 24)
= 1/3(79,756(132)
= 1/3(10.527,792)
= 10.527,792/3
= 3.509,264 CM³