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Kelas : XI SMAmapel : matematika
kategori : suku banyak
kata kunci : nilai polinomial
kode : 11.2.5 [matematika SMA kelas 11 Bab 5 suku banyak]
Pembahasan:
diketahui:
f(x) =
g(x) = x³ - 4x² - 2x + 6
h(x) = 2f(x) - 3g(x)
ditanya
h(x) dan h(-1) = ...?
jawab:
h(x) = 2f(x) - 3g(x)
= 2(2x^5 -x³ -2x + 5) -3(x³ -4x² -2x + 6)
= 4x^5 - 2x³ - 4x + 10 - 3x³ + 12x² + 6x - 18
= 4x^5 - 5x³ + 12x² + 2x - 8
h(-1) = 4x^5 - 5x³ + 12x² + 2x - 8
= 4(-1)^5 -5(-1)³ + 12(-1)² + 2(-1) - 8
= -4 +5 +12 - 2 -8
= 13 - 10
= 3
tanda ^ = pangkat
selamat belajar
salam
bana