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Kubus ABCD,EFGH , s = 6 cm
Perhatikan ΔAFG , siku siku di F
AG = 6√3
AF = 6√2
FG = 6
T pada AG sehingga FT tegak lurus AG
FT = jarak F ke AG
gunakan kan rumus luas segitiga
1/2 x FT x AG = 1/2 x AF x FG
atau FT x AG = AF x FG
FT = AF x FG / AG
FT= (6√2 x 6 )/(6√3)
FT = 6√2/√3 = (6/3)(√2)(√3)= 2 √6