Jawaban:
Diketahui
s = 5 cm
t = 4 cm
π = 3,14
Jawab
a. sebutkan ada berapa sisi kerucut
Sisi Krucut ada 2
b. berapa panjang diameter alasnya
r = √s² - t²
r = √ 5² - 4²
r = √ 25 - 16
r = √9
r = 3 cm
d = r x 2
d = 3 x 2
d = 6 cm
c. hitunglah luas permukaan kerucut
L = π r (s + r)
L = 3,14 x 3 x ( 5 + 3)
L = 3,14 x 3 x 8
L = 75,36 cm²
d. hitunglah volume kerucut
V = ⅓ x π x r x r x t
V = ⅓ x 3,14 x 3 x 3 x 4
V = 37,68 cm³
a).sisi kerucut ada 2 yaitu sisi alas dan sisi selimut
[tex]b).r = \sqrt{ {s}^{2} - {t}^{2} } = \sqrt{ {5}^{2} - {4}^{2} } \\ \sqrt{25 - 16} = \sqrt{9} = 3 \: cm \\ d = 2 \times r = 2 \times 3 \: cm = 6 \: cm \\ \\ c).luas \: permukaan \: kerucut \\ \pi \times r(r + s) \\ 3,14 \times 3 (3 + 5) \\ 9,42(8) \\ 75,36 \: {cm}^{2} \\ \\ d).volume \: kerucut \\ \frac{1}{3} \times \pi \times r \times r \times t \\ \frac{1}{3} \times 3,14 \times 3 \times 3 \times 4 \\ 37,68 \: {cm}^{3} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
Diketahui
s = 5 cm
t = 4 cm
π = 3,14
Jawab
a. sebutkan ada berapa sisi kerucut
Sisi Krucut ada 2
b. berapa panjang diameter alasnya
r = √s² - t²
r = √ 5² - 4²
r = √ 25 - 16
r = √9
r = 3 cm
d = r x 2
d = 3 x 2
d = 6 cm
c. hitunglah luas permukaan kerucut
L = π r (s + r)
L = 3,14 x 3 x ( 5 + 3)
L = 3,14 x 3 x 8
L = 75,36 cm²
d. hitunglah volume kerucut
V = ⅓ x π x r x r x t
V = ⅓ x 3,14 x 3 x 3 x 4
V = 37,68 cm³
a).sisi kerucut ada 2 yaitu sisi alas dan sisi selimut
[tex]b).r = \sqrt{ {s}^{2} - {t}^{2} } = \sqrt{ {5}^{2} - {4}^{2} } \\ \sqrt{25 - 16} = \sqrt{9} = 3 \: cm \\ d = 2 \times r = 2 \times 3 \: cm = 6 \: cm \\ \\ c).luas \: permukaan \: kerucut \\ \pi \times r(r + s) \\ 3,14 \times 3 (3 + 5) \\ 9,42(8) \\ 75,36 \: {cm}^{2} \\ \\ d).volume \: kerucut \\ \frac{1}{3} \times \pi \times r \times r \times t \\ \frac{1}{3} \times 3,14 \times 3 \times 3 \times 4 \\ 37,68 \: {cm}^{3} [/tex]