Diketahui luas selimut suatu kerucut adalah 220 dm2 jika panjang garis pelukisnya 14 dm tentukan panjang jari jari kerucut tersebut
liliput01
Diket: L selimut kerucut = 220 dm² s = 14 dm Ditanya: r.....? jawab: L selimut = π r s 220 = 22/7 x r x 14 220 = 22 x 2 x r 220 = 44r r = 220/44 r = 5 dm panjang jari2 kerucut = 5 dm
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5dregensleyer
Luas selimut = 220 π x r x s = 220 22/7 x 14 x r = 220 44 x r = 220 r = 220/44 r = 5 cm
L selimut kerucut = 220 dm²
s = 14 dm
Ditanya: r.....?
jawab:
L selimut = π r s
220 = 22/7 x r x 14
220 = 22 x 2 x r
220 = 44r
r = 220/44
r = 5 dm
panjang jari2 kerucut = 5 dm
π x r x s = 220
22/7 x 14 x r = 220
44 x r = 220
r = 220/44
r = 5 cm