Diketahui luas permukaan sebuah tabung 720TT cm. Jika perbandingan panjang diameter dan tinggi tabung 4:3, diameter tabung tersebut adalah... A.12 B.18 C.20 D.24
AnandaHafidhR
D : t = 4 : 3 r : t = 2 : 3 r : t = 2a : 3a lp tabung = 2πr(r+t) 720π = 2π x 2a(2a+3a) 720 = 2 x 4a²+6a² 720/2 = 10a² 360 = 10a² a² = 360/10 a² = 36 a = √36 a = 6
d = 4a d = 4.6 d = 24
0 votes Thanks 3
5dregensleyer
Luas permukaan 720 π = 2 x π x r ( r + t) 720 = 2 . 2a ( 2a + 3a) 720 = 4a ( 5a) 720 = 20a² 720/20 = a² 36 = a √36 = a 6 = a diameter tabung 4a = 4 x 6 = 24 cm
r : t = 2 : 3
r : t = 2a : 3a
lp tabung = 2πr(r+t)
720π = 2π x 2a(2a+3a)
720 = 2 x 4a²+6a²
720/2 = 10a²
360 = 10a²
a² = 360/10
a² = 36
a = √36
a = 6
d = 4a
d = 4.6
d = 24
720 π = 2 x π x r ( r + t)
720 = 2 . 2a ( 2a + 3a)
720 = 4a ( 5a)
720 = 20a²
720/20 = a²
36 = a
√36 = a
6 = a
diameter tabung
4a = 4 x 6
= 24 cm
jawabnnya D