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V = 1/3 x 12 x 12 x 24
V = 144 X 8
V = 1152 cm3.
Jika luas permukaan yg ditanyakan, kita perlu mencari tinggi sisi tegak dahulu dengan menggunakan pythagoras :
Tinggi^2 = 24^2 + 6^2
Tinggi^2 = 576 + 36
Tinggi^2 = 612
Tinggi = akar 612
Tinggi = 6 akar 17 cm
Lp = (12 x 12) + ( 4 x 1/2 x 12 x 6 akar 17)
Lp = (144 + 144 akar 17) cm2
tΔ² = 6²+24²
= 36 + 576
= 612
tΔ = √612
= √36×√17 = 6√17 cm
L = (12×12) + ()
= 144 + 144√17 cm²
= 144 + 593,73
= 737,73 cm²