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luas segitiga AFC = 1/2. AC . AF sin60 = 1/2 . 10√2 .10√2 . 1/2√3
= 50√3
jarak F ke AC = garis tinggi dari F ke AC tegak lurus misal FO (O pada AC)
Luas AFC = 1/2 . AC . FO
50√3 = 1/2 . 10√2 . FO
FO = 10√3/√2 =5√6