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s= 10 cm
T titik potong diagonal DB dan AC
buat Δ TCG , siku siku di C
CT = 1/2 AC = 1/2 (10√2)= 5√2
CG = 10
GT = √(CG²+CT²)
GT = 5√6
< CG, BDG = <CGT
cos <CGT = CG/GT = 10/(5 √6)= 2/√6 = (2/6)√6 = 1/3 √6