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a. G ke BD = OG
OG = √GC²+OC² --> OC = 1/2 diagonal bidang kubus
= 1/2 s√2
= 1/2 .2. √2 dm
= √2 dm
OG = √(√2)²+2²
= √2+4
= √6 dm
b. H ke bidang ACF = HT
HT = √HF² - FT² --> HF = diagonal bidang kubus
= s√2
= 2√2
FT = 2/3 OF --> OF = OG pada gambar a
= √6
=2/3 √6
sehingg HT = √(2√2)² - (2/3 √6)²
= √8- 4/9 . 6
= √8 - 8/3
= √ (24-8) / 3
= √ 16/3
= 4 /√3
= 4/3 √3 dm
atau
HT = √OH²-OT²
= √ (√6)² - (1/3. √6)²
= √ 6 - 6/9
= √54-6 / 9
= 1/3 √48
= 1/3 √16.3
= 4/3 √3 dm