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EP^2 = 8^2 + 4^2
EP = PC = 4V5 cm
untuk segitiga PEC
=1/2(2 x 4v5 + 8v3)
= 4(v3+ v5)
L=1/2. 8v3 . P-EC = v
(4(v3+
v5)(4(v3+ v5) - 4v5)
Jarak titik P ke EC = 4V2
cm
rusuk 10 cm
p adalah titik tengah FG
pF = pG = 5 cm
pC =
=
=
=
misalkan titik tengah CE adalah O
CE = diagonal ruang =
OE = OC =
pO =
=
=
=
=
jadi jarak titik p ke garis CE =
semoga membantu :) jadikan yang terbaik ya:))