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sudut antara BD dan BCHE ada di titik B pada segitiga BDH
Panjang BD² = AB² + AD² = 6² + 6² = 36 + 36 = 72
BD = √72 = 6√2
BH² = BD² + DH² = 72 + 6² = 72 + 36 = 108
BH = √108 = 6√3
DH = 6
sin B = DH / BH
= 6 / 6√3
= 6 √3 / 18
= (1/3) √3