Question

Diketahui kubus ABCD EFGH, nilai tangeb sudut CG dan bidang BDG adalah..

Answer 1

Misal rusuk kubus = a
AC = diagonal sisi = a√2
CG = rusuk = a
buat T titik potong BD dan AC,
dan TC = 1/2 AC = 1/2 a√2
α = ∠(CG, BDG) = ∠CGT
tan α = tan ∠CGT = TC/CG = (1/2 a√2)/(a) = 1/2 √2