Question

diketahui koordinat titik p (-1,-3) q (3,-2) dan R(2,3). jika vektor pq = rs koordinat titik s adalah​

Answer 1

jwb

|pq| = √xq - xp^2 + yq - yp^2

= √3 - -1^2 + -2 - (-3)^2

= √4^2 + 1^2

= √16 + 1

= √1

rs = pq = ∆x, ∆y (vektor rs)

∆x = xq - xp = 3 - (-1)

= 4

∆y = yq - yp = -2 - (-3)

= 1

xs = xr + ∆x = 2 + 4

= 6

ys = yr + ∆y = 3 + 1

= 4

koordinat titik s = (6,4)