Diketahui keliling belah ketupat 52 cm, jika panjang salah satu diagonalnya 24 cm maka luasnya adalah..
liwonsubagyo
Keliling = 4 x s 52= 4 x s s = 52 : 4 = 13cm diagonal yang lain = √ 13² - 12² = √169 - 144 = √25 = 5 x 2 = 10c√m L. = d1 x d2 2 = 24 x 10 2 = 120cm²
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DethaViana
K = 4 × S 52 cm = 4 × S S = 52 cm ÷ 4 S = 13 cm
52= 4 x s
s = 52 : 4
= 13cm
diagonal yang lain = √ 13² - 12²
= √169 - 144
= √25
= 5 x 2 = 10c√m
L. = d1 x d2
2
= 24 x 10
2
= 120cm²
52 cm = 4 × S
S = 52 cm ÷ 4
S = 13 cm
D₂ = √S² - D₁²
D₂ = √13² - 12² (12 didapat dari 24 ÷ 2)
D₂ = √169 - 144
D₂ = √25
D₂ = 5 cm × 2
D₂ = 10 cm
Luas = D₁ × D₂ ÷ 2
Luas = 24 cm × 10 cm ÷ 2
Luas = 120 cm²