Diketahui keliling belah ketupat 40 cm.jika panjang salah satu diagonalnya 12 cm maka luas belah ketupat tersebut adalah...cm²
5dregensleyer
D = 1/2 x 12 = 6 cm s = 40 : 4 = 10 cm diagonal lainnya d = 2 x √ 10² - 6² = 2 x √100 - 36 = 2 x √64 = 2 x 8 = 16 cm luas = 16 x 12 /2 = 16 x 6 = 96 cm²
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AnandaHafidhR
K belah ketupat = 4 x sisi miring 40 = 4.s 40/4 = s s = 10
s = 40 : 4 = 10 cm
diagonal lainnya
d = 2 x √ 10² - 6²
= 2 x √100 - 36
= 2 x √64
= 2 x 8
= 16 cm
luas = 16 x 12 /2
= 16 x 6
= 96 cm²
40 = 4.s
40/4 = s
s = 10
s² = (1/2 d₁)² + (1/2 d₂)²
10² = 6² + (1/2 d₂)²
100 = 36 + (1/2 d₂)²
100 - 36 = (1/2 d₂)²
64 = (1/2 d₂)²
1/2 d₂ = √64
1/2 d₂ = 8 cm
d₂ = 8.2
d₂ = 16 cm
L = 1/2 x d₁ x d₂
L = 1/2 x 12 x 16
L = 6 x 16
L = 96 cm²